Confused About Multiple Side Pots
Sep/080
Hi,
My question has something to do with the most “tragic” experience I ever had at the table. It actually happened last weekend.
Four people were in and two of them were both all-in, thus implying 1 main pot, and two side pots. In the middle of the game an argument occurred and I’m not sure if we’ve handled it properly.
Well, the argument concerned player 1 who went all in with $50 followed by player 2 who made call for $50. Player 3 raised $50 after and player 4 followed by player 2 made a call. By the way, player 4 call for $50 + $50 and player 2 for $50.
In total, the main pot was $200 and side pot 1 was $150. River afterwards was dealt and right after player 2 placed a bet of $50. Player 3 call for $50 all in, player 4 raised $50 then player 2 for $50 all in.
The main pot remained at $200, while side pot 1 became $300 and then there was side pot 2 at $100.
I’m not sure but I believed that time that the following players are qualified to the following pots:
main = all players
side pot (1) = players 2, 3 and 4
side pot (2) = players 2 and 4
Am I right for thinking that way? By the way, how is the winner of each pot be decided supposedly? I mean, which order is each pot decided? I’m confused. Please help me.
Thank you.
Haliey
Haliey,
You did a fantastic job following the action. You are correct in who was qualified for the different pots. In regards to how the pots are decided, it goes in order of the last pot created. In the example, side pot 2 would be determined first. The loser of side pot 2 is subsequently eliminated from contention from the other two pots. Next, side pot 1 is awarded, and the winner of side pot 1 shows against the main pot all in player for the main pot.
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